思路：找「右侧第一个 ≤ cur」的元素 → 弹出所有 cur 的元素，栈顶即为折扣。最终价格 = cur - 折扣（有则）或 cur（无则）。
int minIdx = i; // 假设当前位置是最小值
We can run some number of phases every allocation, and tune the，详情可参考WPS下载最新地址
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，详情可参考搜狗输入法下载
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Luce said he was "reserving judgement" whether there would be a similar policy for new cars until all responses to the consultation had been reviewed.